Derivative & Integral
f(x) = x^3 + 2x + 3
Coefficients (ascending powers — leftmost is the constant term):
Each box is the coefficient of x^i. Integers, decimals or fractions.
= 3x^2 + 2
Step-by-step solution
- 1
Differentiate the polynomial
Apply the power rule d/dx [a·x^n] = n·a·x^(n-1) to x^3 + 2x + 3.
- 2
Derivative of the constant term
d/dx [3] = 0 (constant drops out)
- 3
Apply the power rule to the degree-1 term
- d/dx [2·x] = 1·2·x^0 = 2
- 4
Apply the power rule to the degree-3 term
- d/dx [1·x^3] = 3·1·x^2 = 3·x^2
- 5
Result
d/dx [x^3 + 2x + 3] = 3x^2 + 2
About derivatives & integrals
The derivative measures the instantaneous rate of change. For polynomials the power rule does all the work: the derivative of a·xⁿ is n·a·xⁿ⁻¹, applied term by term.
Integration reverses the process — a·xⁿ integrates to a·xⁿ⁺¹/(n+1) — and the definite integral computes the signed area between the curve and the x-axis via the fundamental theorem: F(b) − F(a).
Because everything is polynomial algebra over exact fractions, the results here are symbolic and precise — not numerical difference quotients or quadrature approximations.